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上一篇文件分享了通过opinfo函数获取全局最大最小值,下面的代码将通过opinfo函数获取每个刀具及每个操作的最大最小值,相较于其他方法,这个更直观,同时扩展性也更好。
5 T; W& R6 w# ]) c, W特别说明:
. n: `3 L0 ^# |1 @* Q此最大最小值仅适用于在换到位置输出,不支持在程序头刀具清单里面输出
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后面将会发布获取全局,刀具,操作X,Y最大最小值的相关代码。
- X( J% F( p' d' f6 _- %
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- (TEST)2 h& O6 h4 l/ n% l
- (DATE=DD-MM-YY - 14-12-21 TIME=HH:MM - 20:06)
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- (------------------------------)9 [( ?, ~" ]! D) e+ R
- OAL MAX Z= 1.5( T5 U: r2 U ^
- OAL MIN Z= -.12
3 T6 u [9 x5 P7 k" K2 X, I6 B - (------------------------------)
+ g6 ?+ N2 g' Y! q - G20" J% ^ }/ r9 ~ j# L& L1 O6 W
- G0 G17 G40 G49 G80 G90, N0 \8 {' x! ?/ G6 m' h; f, h& m* F
- (ROUGH PROFILES)
& B( S6 s8 ~) I# X - (------------------------------): Y* J3 E) m2 A6 \- J( j
- MAX TOOL Z = 1.5
" a0 @( ]3 _$ q- ` - MIN TOOL Z = -.12" [/ R" d" R2 x* {) M
- (------------------------------)
: h" Y& w* c" J" Q* k5 ] - MAX OP Z = 1.5- @, v4 p" @5 H+ d6 f$ I/ M6 _6 a
- MIN OP Z = -.12
% K( B7 t' Q3 c8 Q4 @3 _ - (------------------------------)
% Y; V/ ?! ~! i M! m - T3 M6
. }+ R$ q" T5 U% w, }, A: X - G187 P3 E.001
# B6 {. E1 d7 h* X m+ n - G0 G90 G55 X-15.1795 Y-.7705 C0. S10000 M3
3 `$ T+ C+ x3 J! C$ f! A& `( H6 v* P* ] - G43 H3 Z1.5
6 q. ^' m, z6 F3 y - M8) D3 N% ~2 G( c
- Z1.1949
8 }; c( {6 F+ p/ R+ W - G1 Z-.12 F300.8 O ?- b+ A. U. o
- X-15.4662 Y-.3609 F150.
- S3 \6 H6 e% w: e" K# l5 e1 Y$ x, f - G3 X-15.4775 Y-.3475 I-.082 J-.0573$ c. T) C; e( k% n j
- G1 X-15.5365 Y-.2885$ q( N+ `! x, d# [$ l6 B- l
- G2 X-15.7049 Y.1181 I.4066 J.4066. q5 ]2 P! r- ^: a6 B+ @
- G1 Y4.4823
" P/ `4 g+ z" z: F0 ]# L3 Y( C - X-15.4184 Y4.7688& `/ v( e) T% V! z+ `- I; q
- G2 X-15.0118 Y4.9372 I.4066 J-.4066
; \7 j2 E" ^: q2 Q1 I - G1 X-14.3309
2 C, n2 s- r! ~" r - X-14.2453 Y5.0041
. g6 y7 e e4 ]# W1 B) h# o% R2 o - X15.2342
' n0 r: Y& P1 D& V - X15.5995 Y4.63897 Y! ]5 ]) J! y! {7 j
- G2 X15.7679 Y4.2323 I-.4066 J-.4066
7 h4 u4 \$ a) Q! i - G1 Y.1968+ A! h" ~2 U/ S
- G2 X15.5995 Y-.2097 I-.575 J0.: F2 ^$ i; l: A5 W8 c: d/ l" f6 M% I) b
- G1 X15.2342 Y-.575, N# q+ ^) g( a/ ]5 T
- X11.428
7 i6 d, U; C, V( {" G& ~+ d - G2 X10.9577 Y-.4661 I-.0385 J.9035" n% \6 U" O) `9 b* ~8 h3 i; b
- G1 X9.163 Y.64555 M1 Q! U( _7 S' j* _/ [7 s
- X3.9039# `8 ^ i4 w( M$ }+ \
- X2.1508 Y-.44159 U& U5 z" T# u0 m/ A+ m, j! b3 j
- G2 X1.6819 Y-.575 I-.4689 J.7564
M% [, r3 j7 U2 `: v5 _5 p2 q8 Y1 _ - G1 X-.58622 r& ~* [4 _/ U0 h
- X-15.0118
+ u8 P) d5 w' }& T! Q2 M - G2 X-15.4184 Y-.4066 I0. J.575
: u5 E* s9 ?3 |: w - G1 X-15.4775 Y-.3475+ K3 Q( P. {2 }; J9 h! V4 {; D
- G3 X-15.4908 Y-.3363 I-.0707 J-.0707$ h" Z- k5 q3 D1 f
- G1 X-15.9004 Y-.0495
4 D) g0 |) U4 _, A - G0 Z1.5
2 o4 `, @8 X+ E& F6 i - (ROUGH POCKET #1 WALL)$ B! |$ b+ a z: Z! Q
- (------------------------------)
% F3 K/ m: L8 D8 ] W. J - MAX OP Z = 1.5
- P" Z* y, ]% V$ {" @' E - MIN OP Z = .12
0 v( Y8 W( G4 B, k6 Z8 u - ​8 r- P% }0 S3 u- C2 ]+ y. X
- G187
6 S0 I; ~) P Z1 ~/ k; S4 t9 y - X-10.9533 Y2.3478
' P8 P5 e. }( {) I8 Y9 r, P4 s - Z1.19497 m# \; J9 g( W' D! I4 N; \
- G1 Z1. F300.& p1 x" `& Z5 J5 v
- X-11.3196 Y2.8576 Z.12: @7 g3 K3 C( T
- X-11.3505 F150./ ~2 d, w4 V1 y
- G2 X-11.6542 Y2.3622 I-1.4172 J.5282
( `5 \% g! B3 f1 k - X-11.3196 Y1.7751 I-1.1135 J-1.0236
& M! F) t2 l0 u - G1 Y2.8576
4 C3 d, K/ ?4 B1 u& J - X-11.3378 Y2.8393
9 h: x1 w* h# A, t- I: j; P* B+ B1 G - G3 X-11.5873 Y3.1701 I-3.6384 J-2.4843
& n1 Z. k1 d" U( K9 g" k4 W% G* s - G2 X-12.1415 Y2.3622 I-1.1804 J.2157
- T# ~. @- c5 D2 F, n: t! w - X-11.5677 Y1.3386 I-.6262 J-1.02368 v/ K4 i1 I7 A' }# I+ ~6 a
- G1 Y1.263" X S7 `5 f6 B0 U8 K. Q: D/ r
- X-11.0071# e7 L* s5 n5 ^7 a, e$ f$ |
- Y3.1701* @3 z+ z/ _% e% G
- X-11.5873
J# `5 X6 E |: S - X-11.5874 Y3.17' [9 ]+ E N' {* Q
- G3 X-11.7835 Y3.3858 I-2.4389 J-2.0183 d. m* j* P( K
- G1 X-12.1927+ D$ l$ p, X) B
- G2 X-12.7677 Y2.8108 I-.575 J0.
( V! g5 A5 G- @5 s( e& k - G1 X-14.3187/ A: `' n! a _1 } Q& m
- Y2.40529 ^. W! _2 A9 Z0 U% e8 v9 G
- G2 X-14.488 Y1.9978 I-.575 J0.
& I4 _& x, l- Y& @9 n5 \ - G1 Y1.9136- Y7 k/ g) i# m- j( Y
- X-12.76773 r+ X s2 T" Z% o
- G2 X-12.1927 Y1.3386 I0. J-.575
( f7 m0 J1 m; A7 H8 P7 q/ y' g - G1 Y1.2598
0 I" P& K) N3 L; H$ X - G2 X-12.7677 Y.6848 I-.575 J0.
# ]) F4 i) n/ j - G1 X-14.3187. v& ^: v1 a- Y8 |- A; I
- Y.638
9 V. b5 V1 q/ Z" ?, V - X-10.3821+ F4 Y. ]0 q+ u W# p/ [
- Y3.7951: M' u# Q& x; W- |# {- T8 h
- X-12.2972- @) S, f" E( @
- G2 X-12.1927 Y3.4646 I-.4705 J-.3305 |/ ]1 [3 |! ?7 m) U7 w
- G1 Y3.3858
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- M5
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- G28 X0. Y0. C0.; v6 F$ [3 {6 F8 A5 X: d
- M30
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复制代码 ) Q' R5 {( b$ ~; y4 C) S
代码和步骤正式开始:
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! Y7 [9 P+ C" g A6 M2 `) C5 @1:在任意2个代码块之间增加以下代码,如有重复,需要更名。
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/ z# z0 W% d! H2 s! a, u7 K6 n以下代码为获取单个刀具最大最小值,多次调用,会有多次不同的结果。
q+ w; J! _9 x4 Z- pcomm_max_min_for_tool
' g# J6 m1 N6 f2 }9 Q# H( v8 U - z_min_tool = opinfo(19, 0)5 u- q' h" Q2 u0 o9 B7 s- s
- z_max_tool = opinfo(16, 0)/ b2 w- M/ z9 I, r$ N
- loop = 14 j- F( Z( i4 q' J# Q5 u
- result = opinfo(92, loop)0 P% |* B, s) c
- while result = 1000,6 v& O9 E9 v2 k9 }3 {* [4 s
- [: n# Q$ q$ {/ j2 p
- z_min_op = opinfo(19, loop)
+ ~2 c [: M* ]) g; {+ T8 t - z_max_op = opinfo(16, loop)7 R. }) _3 E( S9 S
- if z_min_op < z_min_tool, z_min_tool = z_min_op
0 {2 r- i. k0 q9 |/ s8 U0 m - if z_max_op > z_max_tool, z_max_tool = z_max_op. R- e' E9 x: x
- loop = loop + 1/ p' ~8 ^! o7 d, \
- result = opinfo(92, loop)0 h7 h$ A J1 G- _5 x5 C
- ]3 z- h5 ~( P5 [/ a) ^, e
- "MAX TOOL Z = ", *z_max_tool, e$ 7 \/ d2 d: r5 t& T
- "MIN TOOL Z = ", *z_min_tool, e$
复制代码 9 x1 E! N& y, l! x7 _& o
2:在任意2个代码块之间增加以下代码,如有重复,需要更名。8 F" k+ t1 _7 ~5 d( ^* c
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以下代码为获取单个操作的最大最小值。" R9 e5 L7 @$ \3 W* `1 b" G2 H
- pcomm_max_min_op 0 C; |( d+ @, |) W# C
- zmin_op = opinfo(19, 0)% V* Q2 X1 R) L+ V5 ?* N
- zmax_op = opinfo(16, 0)
* I7 }9 K' L; n m$ f: x: Z - "MAXIMUM OPERATION DEPTH = ", *zmax_op, e$
6 n0 [! _9 _3 }9 ^% n5 p - "MINIMUM OPERATION DEPTH = ", *zmin_op, e$
复制代码 3:在psof$,ptlchg$ 换刀代码前增加如下代码:. {+ h4 ]4 L% j0 H0 E) E2 `
- pcomm_max_min_for_tool+ [! `: q$ \* |' l5 H: \
- pcomm_max_min_op
复制代码
- q @0 Y, L+ u* Y+ `4:在ptlchg0$增加如下代码:) w( O/ ^9 K( A3 s3 _8 I
以下代码可能还需要判断当前操作和前一个操作的id是否相同$ G7 h: G R' _+ P% g d4 ]/ b
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