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上一篇文件分享了通过opinfo函数获取全局最大最小值,下面的代码将通过opinfo函数获取每个刀具及每个操作的最大最小值,相较于其他方法,这个更直观,同时扩展性也更好。* b1 s- z& _8 y$ p; \; J
特别说明:7 a4 V4 ^4 U+ i7 c
此最大最小值仅适用于在换到位置输出,不支持在程序头刀具清单里面输出; n i5 F& [1 m7 y F& o! S
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后面将会发布获取全局,刀具,操作X,Y最大最小值的相关代码。! w! V6 Q( H# H1 G) H6 Q6 `: f1 ?9 X
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- (TEST)
# q0 s( Z" ]0 x3 I, S' l" C - (DATE=DD-MM-YY - 14-12-21 TIME=HH:MM - 20:06)
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- v$ @# O3 K5 |0 C) C2 q- U- T - (------------------------------)
1 l E5 M6 G1 d- a! G3 B7 T - OAL MAX Z= 1.5
8 Z5 A/ s" |+ d x) u - OAL MIN Z= -.12$ G G, ~7 \6 @. \6 V) `- m
- (------------------------------)
9 M9 U3 z* }: t. @* b. B+ \ - G20- N4 R% ^& ~; _$ g" F% s
- G0 G17 G40 G49 G80 G90
& s# V: C7 [* h0 X - (ROUGH PROFILES)
. Y9 r4 K! Z; Y- ^- H - (------------------------------)% p4 k: v( b |
- MAX TOOL Z = 1.5
: s3 R, [* I: k J - MIN TOOL Z = -.127 v/ h# |& ^% L; y- p2 g- ~4 E$ U
- (------------------------------)
0 p& i6 ?! c* P+ j - MAX OP Z = 1.5
1 X1 |: {) s p+ z9 ?/ r' }1 q* r - MIN OP Z = -.12
% M* I3 `0 b F$ m8 \ - (------------------------------)7 d# |+ D1 j7 B3 \+ g Q
- T3 M6
/ [6 |/ g/ b, E2 I4 R/ I. v/ g6 D+ J - G187 P3 E.001
; S" |- C# R$ k0 p6 I, S - G0 G90 G55 X-15.1795 Y-.7705 C0. S10000 M3
4 E( B' H& O; r! T - G43 H3 Z1.56 z! r3 l7 _7 F0 j# ]
- M8. d! n2 j3 L$ F- {. V+ h1 u
- Z1.1949( ^) i; i+ f6 U9 B" M+ q2 z5 n% ]
- G1 Z-.12 F300.
K3 h. I% F& v - X-15.4662 Y-.3609 F150.
: r" i* w# G+ _! B. } - G3 X-15.4775 Y-.3475 I-.082 J-.0573
% P, M7 b6 B& x8 |/ j- r - G1 X-15.5365 Y-.2885. V* }- F7 x$ p6 M3 x3 g/ U
- G2 X-15.7049 Y.1181 I.4066 J.4066; d+ X* F3 S" x1 j. Q
- G1 Y4.48231 q- @, b: q- Z: p h1 a- X
- X-15.4184 Y4.7688) t) W+ \" i( C* }( ^8 }1 m/ `: a
- G2 X-15.0118 Y4.9372 I.4066 J-.40666 H$ p: Z+ _- u% ~% j
- G1 X-14.3309, Y- A5 q9 s( p; x5 k8 F: A$ T
- X-14.2453 Y5.0041# d0 E" T$ v' }" v
- X15.2342& @- C! J5 k5 p
- X15.5995 Y4.6389* N# }0 N- S$ J# f) T. E5 ?% c
- G2 X15.7679 Y4.2323 I-.4066 J-.4066
N; {1 F2 j. _9 e+ c5 } - G1 Y.1968
) j# _; |; @3 _$ Z" n7 c. P% @ - G2 X15.5995 Y-.2097 I-.575 J0.
+ w8 ^& t ]+ A0 M6 d - G1 X15.2342 Y-.575
5 d1 l, o! Z( J/ G- D0 j7 g - X11.428/ P( j) d5 F ]5 C& ~. D4 E p
- G2 X10.9577 Y-.4661 I-.0385 J.9035, c. h) r/ Z9 r, S6 j$ V5 a6 N
- G1 X9.163 Y.6455' Q+ R* ~: C0 j2 z# z: C+ r
- X3.9039. i, t1 q- j2 q T h
- X2.1508 Y-.44150 P3 t0 L" W" _5 e$ u
- G2 X1.6819 Y-.575 I-.4689 J.7564
; ~1 F9 c' ~' M; P5 ?, x- n t: O - G1 X-.58624 S( d4 c7 n3 I0 o
- X-15.0118
( n3 _1 V0 V: h& b - G2 X-15.4184 Y-.4066 I0. J.575
6 x) n+ F/ q o$ Z, j$ m - G1 X-15.4775 Y-.3475
& Q" ?3 i. G$ O: u; Z9 _/ ^; b - G3 X-15.4908 Y-.3363 I-.0707 J-.0707
! k" u0 e- {0 W - G1 X-15.9004 Y-.0495
* J d" H3 i% z- e4 P' N - G0 Z1.5
+ x# ]9 _7 j6 e. d S' e8 g - (ROUGH POCKET #1 WALL)" `& s4 q* p" Y* c$ F7 x" G2 H
- (------------------------------)
0 x0 _& x- w7 ?% @ ` - MAX OP Z = 1.5
: S/ ^$ V# m; V! C2 [, p0 {6 T - MIN OP Z = .12- |1 Y) q! U. q, c
- ​
4 ^8 O" e: o$ |; B3 E2 J - G187
( |* K8 ^" Y* {* } - X-10.9533 Y2.3478
6 a* e* L$ {7 p+ K; B5 {. b2 m" r - Z1.1949
. W5 \- _( T4 Q. e% H. Y - G1 Z1. F300.( L5 z; J: |' ? O, S3 e% O3 Y7 e
- X-11.3196 Y2.8576 Z.12- f: E" B8 p$ S2 v8 s
- X-11.3505 F150.) ^; E" E' D }: f! e8 y4 |
- G2 X-11.6542 Y2.3622 I-1.4172 J.5282# m0 _8 D' B3 c8 k1 o- H1 |
- X-11.3196 Y1.7751 I-1.1135 J-1.0236
! f% P* J, ~6 K1 `; k q. }1 g - G1 Y2.8576
8 S+ Z" D6 C* S2 z. }6 [5 O9 [ - X-11.3378 Y2.83939 _& |& G( N$ R2 }: S; P
- G3 X-11.5873 Y3.1701 I-3.6384 J-2.4843
- }2 e- _" A* W - G2 X-12.1415 Y2.3622 I-1.1804 J.2157# ~. A+ Y8 F; T9 Q1 p9 Z) N1 ^6 I
- X-11.5677 Y1.3386 I-.6262 J-1.0236- l4 f q. M. S
- G1 Y1.263
) [! C& r+ a& C# Q, F0 M - X-11.0071
, T$ D% }9 A4 ~5 a - Y3.1701. O. b" ]7 f$ Z
- X-11.5873
) f M9 A: N" _' B% a - X-11.5874 Y3.17
% T4 N$ @7 [4 H* F: X# J4 b% g - G3 X-11.7835 Y3.3858 I-2.4389 J-2.018: ^* A. R9 W4 y: n
- G1 X-12.1927$ d: z2 j' q* z6 R7 R
- G2 X-12.7677 Y2.8108 I-.575 J0.
8 U: T% E8 U/ I2 n0 i - G1 X-14.31873 D$ E! H2 ~) b1 ?
- Y2.4052# D! z1 ]& \: t* h$ t
- G2 X-14.488 Y1.9978 I-.575 J0.
0 S- F0 K( N$ \, _) O4 O' Y - G1 Y1.91362 s' ]5 g9 c! W/ U: ]/ L1 A
- X-12.7677
+ w( ]: w7 a2 o0 A - G2 X-12.1927 Y1.3386 I0. J-.5758 v) F. T9 d1 O+ ~ K, V4 H
- G1 Y1.2598; V x$ U$ M; B( a: a
- G2 X-12.7677 Y.6848 I-.575 J0.
, L m1 ]/ `% g& l7 i3 d - G1 X-14.3187- x$ }7 N8 r5 F, z8 _! ?, `
- Y.6382 [- Z% U3 S& ~
- X-10.3821/ {, \6 p6 i; h- d2 d- \/ p" _
- Y3.79517 G- s n" k6 |0 V1 C/ J
- X-12.2972
& d7 {# E, R( B - G2 X-12.1927 Y3.4646 I-.4705 J-.33053 J6 e! `# z9 J; f
- G1 Y3.38584 h0 u3 ~7 P8 A
- G0 Z1.5& S0 s# `, n/ P: ^$ u" e) Q8 t
- M56 {" _( x: C9 ]6 s
- G91 G28 Z0. M9
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复制代码
+ J$ ?% A& x5 }' c代码和步骤正式开始:" @$ W# J* _2 t( m D
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( ?" v, ~/ T: Q' u7 n1:在任意2个代码块之间增加以下代码,如有重复,需要更名。
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以下代码为获取单个刀具最大最小值,多次调用,会有多次不同的结果。
j7 T* Z/ a, t$ h% a$ K* h7 k- pcomm_max_min_for_tool
7 K* o* B1 R1 F l& p+ B - z_min_tool = opinfo(19, 0)6 c' A" F$ w. ^5 W
- z_max_tool = opinfo(16, 0)
9 M9 W: s& }: ]$ p - loop = 16 l' y* W$ C E- c* Y; D
- result = opinfo(92, loop)
8 X2 y& l% x& X5 J - while result = 1000,
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2 X7 n0 Z( u0 k* V& W - z_min_op = opinfo(19, loop)
- d+ S4 f0 d8 P& q" K - z_max_op = opinfo(16, loop)
! a& j K# U: Y) ]% B$ m$ O - if z_min_op < z_min_tool, z_min_tool = z_min_op
( w' x! w& i8 F: C9 Z - if z_max_op > z_max_tool, z_max_tool = z_max_op9 d. F- E8 |4 K
- loop = loop + 1
6 Q$ C0 I& A/ W- H5 | - result = opinfo(92, loop)
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) e# Y q( R. O/ V: W - "MAX TOOL Z = ", *z_max_tool, e$
% }( |, P, n( A3 Z; W2 Y& c6 j - "MIN TOOL Z = ", *z_min_tool, e$
复制代码 & H: r" e6 g2 ^0 G$ P/ E: A) x
2:在任意2个代码块之间增加以下代码,如有重复,需要更名。9 t* t; y* c3 `& a; R: g$ Q
% r; N" d% G* }以下代码为获取单个操作的最大最小值。
& e" D: x: C1 g# t- c' R- pcomm_max_min_op * L/ V7 g) ?; I0 z8 N) W
- zmin_op = opinfo(19, 0)! Q5 a% @" x$ d
- zmax_op = opinfo(16, 0)3 Y" \( G( o7 o- r6 G9 y
- "MAXIMUM OPERATION DEPTH = ", *zmax_op, e$
' a0 G; v3 t( j) L+ h. X6 Q - "MINIMUM OPERATION DEPTH = ", *zmin_op, e$
复制代码 3:在psof$,ptlchg$ 换刀代码前增加如下代码:
) ]4 F; D5 X( p' @ n- pcomm_max_min_for_tool
/ K# c9 g9 O! C0 j - pcomm_max_min_op
复制代码 0 k5 G2 o& Y6 `1 z1 T$ `5 B
4:在ptlchg0$增加如下代码:, p! L# O' p4 K: g( c% m L
以下代码可能还需要判断当前操作和前一个操作的id是否相同
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