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发表于 2011-12-9 08:24:57
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本帖最后由 christzyy 于 2011-12-9 08:43 编辑
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不好意思全是E文 我有时间会翻译好 这里不是针对2800的 但和2800有千丝万缕的联系
1 e' [6 O/ M6 s, C, k+ f代码的编号是从000开始到900结束 长代码也要按这个方式断开 开头是第几段编码 用（*** START INS ** 开头代码是不是必须这样我不确定） 结尾必须是（*** END NEWPART）（*** END） *表示数字
" B7 [$ U2 [ H! e2 g9 a一楼的代码是我用软件编辑过 所以编号不对 发上来时忘记改回来了
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5 A4 V! A/ p5 d9 nLine 849 - Shows start of program, inches mode, prog. no. 20
: K% S: W$ U' [% |Line 850 - Tool Dia. .125 in
B6 [9 M, b# s& i2 ?Line 851 - Feed Rate on X and Y axes to 16 in/min
6 z; [5 @3 c! ~) LLine 852 - Feed Rate on Z axis to 5 in/min8 C1 h6 I5 b1 ?9 ^' O
Line 853 - Halts the program and prompts you to set up the axes (if that's not in the manual, let me know and i'll go into more explanation)
j- q4 h# z- E( xLine 854 - Turns on the spindle, note on the left side of the spindle there's a switch that if turned off will keep the spindle from starting, also there's a local/program switch on the left front of the yellow box that transfers control of the spindle to the program)/ ?# g. h0 k" o! y" f4 y
Line 855 - "GO Fast" (rapid traverse) to X = -.31256 S3 H( N- e( N8 m0 ?
Line 859 - GO to Z = -.3750 (at defined feedrate)
5 {8 b, O) c: HLine 864 and 865 - using only one GO command and specifying two axes will do linear interpolation on those two axes (note that on this example that the Y axis is already there so it isn't obvious, this was a move to drill a hole, and mastercam likes to specify points that we're already at quite often)
9 `3 s2 |: I8 g5 _" S; X; ]! i1 hLine 873 - turns off the coolant that was mysteriously never turned on using the COOLANT ON command.
g" T5 [ q6 y4 D' qLine 874 - raises spindle above clearance plane" L. |2 f% c( i
Line 875 - turns off spindle
* J+ m0 I" M' O( |* _Line 876 - shows where program ends and gets machine ready to run it again.5 n. H2 r0 {0 ]2 h
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.....
9 `7 c+ f7 U3 L; x; o3 c+ l849 START INS 20
: k: }1 _, u/ y* H4 ?* H p850 TD = .125( x; }( e- F2 j. Z2 j
851 FR XY = 16
" w5 H& z8 b& K, R% Z1 H4 Z$ L- d852 FR Z = 5
0 `+ L8 m# k8 }( i0 _( i# ?853 SETUP >ZCXYU
& H% c0 C# F& q+ G$ r8 r854 SPINDLE ON
2 {: @. u0 ^) b& Z/ t- n855 GOF X-.31252 d3 S/ J! L: q; o; V+ Q- M
856 GOF Y-1.1875
, W5 a; d# L$ H" X' [) x857 GOF Z.1000
, f5 J9 _$ x* B3 D1 G# X6 @858 FR XYZ = 4.1" L0 u) x- t$ X: e7 a0 C
859 GO Z- .37509 U0 _/ @: U# }' J( n# |3 L8 ]8 D
860 GOF Z.1000
% A5 Z+ O) \9 I n1 `861 GOF X-1.6250
+ m& {3 ~2 O- E- Z3 |862 GOF Y-.4297& D7 D! h9 T( z/ W4 M+ H
863 FR XYZ = 4.1" H* K" s9 V. @
864 GO Y- .4297
8 o, M$ O. G; ?% E865 Z- .3750
: j( R) O9 k q! Y- W( e( V s866 GOF Z.10008 }- q! g+ {9 T; V+ a
867 GOF X-1.6250: r3 t: ^. X* i. y2 x- d
868 GOF Y-1.94535 _# `; F0 [( u
869 FR XYZ = 4.1
/ r' m# m8 h2 }% Y6 j4 _870 GO Y- 1.94539 ?; L) a1 b9 |) ]- Y H
871 Z- .37505 I- F. S5 D0 p- }2 w) K: v
872 GOF Z.1000. D) o( N9 ~; f0 k' F$ s O
873 COOLANT OFF
- j; p& l- w7 N7 W874 Z>C+ k" l6 h! j; n1 }0 F' t2 y
875 SPINDLE OFF# C* i" C1 W' i4 j+ N
876 END NEWPART, i1 G' g9 [- y+ |
.....1 `# l1 N5 v! y T3 j5 \
. U( t" ?* ~& s. X6 P1 G2 J) Q- GNext segment of code show how to implement a tool change.
( |6 a6 ~. P# D. y* Y7 j+ ]program is running until line 354, which raises the z axis all the way up.
2 e; p' c2 _6 I3 n2 l! Uthen turns off the spindle. HALT will pause the program, allowing time for a tool change, until the "next" button on the keypad, which will resume program execustion, in this case it will turn the spindle back on and start motion again
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352 Z- .3750 . Y3 ?8 J u3 @
353 GOF Z.1000 ; T+ j: z/ s! m2 F" B- j4 z
354 Z>ZMAX ; s7 s* T; {) t1 x. m4 t' u9 z
355 SPINDLE OFF 1 m, ?% [$ X. Y, v# G0 x
356 HALT , F2 | r$ `( ?: }% s2 |
357 SPINDLE ON ! L9 D l. |5 O* K! s8 Q
358 GOF Z.2500 ) d( o* ?4 d' y; N, D1 g
359 GOF X5.0938
( i3 h' i d5 @. _2 [.....
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This next segment show how circular interpolation can be specified.# Y; J7 q8 |2 D+ i4 O% I7 C6 Y
starting at line 14 a local zero is specified to be at at 0,0 on lines 15 and 16. Line 17 tells it to "Go Relative angle" 90 degree CCW motion. (negative values indicate CW), i believe values up to 360 degrees can be used and there is a special command that needs to be used when the center is outside the machining envelope (i think it's an "i" or something, but i've never used it so i can't say for sure). Line 18 executes the move.- J: O9 y' [) ~
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012 GO Z- .0938
7 m+ M, H* a) Y8 i013 FR XYZ = 12.0/ j! Q3 z/ }9 e$ C1 d* y# Q
014 ZERO AT
( ?1 ~7 |4 x) E5 z0 C% T/ K$ F- J015 GO X .0000( Z9 o# p" W6 \! M- k' Q
016 Y .0000
$ i) Y6 z; h& ~9 l9 i017 GR a 90.- i0 w, g3 A ~+ V1 Z4 E$ L
018 >REF COODS2 X, k( Y# P% X2 X$ m
.....1 S6 K; B7 c. {$ I% `* j2 ]
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发表于 2011-12-10 15:18:34