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发表于 2014-7-9 17:43:47
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回复 1# sdafew000 3 u3 b' t' }" M& b, i3 l
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6 S7 x; |, {( \+ \' P 你的后处理不支持螺旋程序,智慧输出G1线段,缺少相应的代码。5 o5 }) k2 G5 I% [/ F+ |
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替换你的原有的即可3 I: q$ c- N# }. `! z$ R* G6 r
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pcirout #Output to NC of circular interpolation
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6 }) _' t: {& ~# z if plane = zero, result = force(xabs,yabs) #force coordinate on full arc 8 v; f. d7 D. A$ `
if plane = one, result = force(yabs,zabs) #force coordinate on full arc
. s( ?5 S/ j5 B# j; } if plane = two,7 a) m2 u( g, i3 D0 ]/ m Y1 v
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result = force(xabs,xabs) #force coordinate on full arc ) S. p% F/ |$ B
result = force(zabs,zabs) #force coordinate on full arc ; p0 @7 u" m) I: `( Y+ O6 d
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if hel_2100 = one, pcirout2
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pcirout1 #Output to NC of circular interpolation
* I7 A6 `: z; a" S5 S pcan1, pbld, sgcode, sgabsinc, pccdia,6 z* Q0 O, S8 ?$ B o1 A
pxout, pyout, pzout, pcout, parc, feed, strcantext, scoolant, e J. {, h6 r0 j; P" U* M. }4 s: H
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fmt "K" 2 lead #Helical lead D4 c+ R: p1 {9 B& g7 d6 ^/ h& Y. u
hel_2100 : no #Acramatic 2100 style helical moves, 0=no, 1=yes: {/ b1 \" ~/ K5 p
5 q" x* v; n4 R( @pcirout2 #Output to NC of circular interpolation' _& Z1 I5 w/ U8 B: g% ^* v
if (plane = zero & fmtrnd(zinc)<>0): J. v6 d. @, m3 v
| (plane = one & fmtrnd(xinc)<>0)
& O3 K0 G7 B8 [) t | (plane = two & fmtrnd(yinc)<>0), phelout) }9 W5 K( i( a `) F
else, pcirout1- m( f; ?: _6 ^1 e, R) m5 Q$ P0 J
1 e M; ?6 r0 e/ w; Jphelout #Output to NC of helical interpolation
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* ~' B" r' R+ x4 N I2 t& e result = nwadrs(strk, lead)
4 r; o% L( O; S) @ lead = abs(zinc/sweep*360)
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if plane = one,% J6 Z7 q, k. A! e
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& E$ C$ C b7 t. T2 x3 y8 T w% o5 O" x result = nwadrs(stri, lead)- I$ U1 W" `: t9 u
lead = abs(xinc/sweep*360)7 B5 o3 c/ e" @ |! l
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8 r1 S/ G* u0 R [0 o! Z. r2 |, Y if plane = two,
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9 O, N+ r: ^- m5 ]1 r& x/ u result = nwadrs(strj, lead)9 @* |3 X: s, q0 c
lead = abs(yinc/sweep*360)
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4 m; ? [. z) q& }( J; M* {+ @ pcan1, pbld, `sgfeed, sgplane, sgcode, sgabsinc, pccdia,
1 b8 g* i$ W4 _7 u! N# Z pxout, pyout, pzout, *lead, pcout, parc, feed, strcantext, scoolant, e |
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