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发表于 2015-12-25 10:33:48
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回复 2# 若枫
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老大:
2 o. `* x+ q* n1 `0 X" |+ S8 W2 C 感谢您的回复!以下是我的方法,这样的确出来两个G代码。
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if drillcyc$ = 9,( z4 F8 m7 p( I. L/ @
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pdrlcommonb2 h9 m; B3 V. G# T- G0 }" F
peck1st =peck1$) ?/ `9 U+ V1 z2 ]
if dwell$ = 0,pcan1, pbld, n$, *sgdrlref, "G1181", pxout, pyout, pfzout,
& `2 o8 K" \7 W; c prdrlout, dwell$, *peck1st, *peck2$, *feed, strcantext, e$$ H' `0 n7 b+ p0 j
else, pcan1, pbld, n$, *sgdrlref, "G1182", pxout, pyout, pfzout,
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pcom_movea
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' A9 l2 Q( Z4 o5 ~但使用以下的方法出不来一个钻孔循环两个不同的G代码。上面的"G1181”用原来的*sgdrill出来的是G81
# W, [: X, _$ Z, e7 u( ?sg85 : "G85" #bore #1 - no dwell ; @# E; `0 D* z* A6 I5 M/ t1 }
sg85d : "G89" #bore #1 - with dwell
1 a4 H |( u$ T( S4 d+ |7 Y. B( Lsg86 : "G86" #bore #2 - no dwell+ [+ u3 k; P1 c/ k
sg86d : "G86" #bore #2 - with dwell
2 |% ~! I% y4 _9 `: p7 F% C! V* Usgm1 : "G76" #fine bore - no dwell
1 }6 t- A) {6 y9 O- M. W! y4 {3 Psgm1d : "G87" #fine bore - with dwell
6 ]; `( \+ d" e2 Psgm2 : "G84" #rigid tap - right hand
5 Z; n6 }; K$ J- ^$ Rsgm2d : "G74" #rigid tap - left hand' @7 A. _$ v( R7 `) G8 P
sgc9 : "G183" #custom #9 - no dwell) T" `1 s) [7 g! o
sgc9d : "G184" #custom #9 - with dwell0 ^8 w9 t6 N9 d8 A* k5 ~
sgc10 : "G185" #custom #10 - no dwell
" n; ]: _0 ?& k0 dsgc10d : "G186" #custom #10 - with dwell
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请指点一二,谢谢!" p/ W) V% b( `6 N
最终我要出25个左右钻孔循环,30多个G代码。 |
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